Parameters of structural diagram

13.1

7.1.4 Calculation of structural diagram coefficients. [L1, section 6.5]
Rated load modes
In all formulas, we assume that Re = 0
1
kо
 = Re2+(Xq + Xe)·(Xd′ + Xe)=0 +(2.33+0.4)·(0.307+0.4) = 1.93
kо = 0.51
K1 — change in electromagnetic torque during a small change in rotor angle and constancy of flux linkage along d axis, i.e. synchronizing torque
K1=  [
ΔMэ
Δδ
] Eq′=Eq0′ = kо · U∞ · { Eqao · [ Re · |

sin(δ−α)

| +

+

 (Xd′+Xe)·cos(δ−α)]

+

Jaqo

·

(Xq−Xd′) · [ (Xq+Xe) ·

|sin(δ−α)|

−
− Re · cos(δ−α) ] }  =0.51·0.65·[ 3.2·(0.307+0.4)·0.39 +
 +0.33·(2.33−0.307)·(2.33+0.4)·0.92] =0.33·[ 0.85 + 1.72 ] = 0.85
K2 — change in electromagnetic torque during a small change in flux linkage along d axis and constancy of rotor angle
K2  = [  
ΔMэ✱
ΔEq′✱
] δ = δ0  = kо·{Jaq0·[Re2+(Xq+Xe)2]+Ead0·Re} =
 = 0.51·0.34·(2.33 + 0.4)2 = 1.29
K3 — reflects the influence of external resistance, independent of load
K3 =  
1
1+kо·(Xd−Xd′)·(Xq+Xe)
 

 

= 

1
1+0.51·(2.33−0.307)·(2.33+0.4)
=0.26